Javascript find in array of objects5/15/2023 ![]() Please show your love and support by sharing this post. If you're unable to use the latest features of JavaScript, then perhaps you can rely on a simple for loop to check if a key in the object of arrays has a certain value. For example:Ĭonsole.log(objs.some(() => name = 'John')) // output: true ![]() In ES6+, we can destructure function arguments to simplify the syntax even more. And then we can convert the set back to an array with the spread operator. Then we can remove the duplicate values with the Set constructor. We can use this to test if a key in the object of arrays has a certain value in the following way:Ĭonsole.log(objs.some((obj) => obj.name = 'John')) // output: true One way to get distinct values from an array of JavaScript objects is to use the array’s map method to get an array with the values of a property in each object. It tests whether at least one element in the array satisfies the test condition (which is implemented by the provided function). Introduced in ES5, the some() method returns a boolean value. let car cars.find (car > car. Find an object in an array by its values - Array.find Let's say we want to find a car that is red. If we wanted to check if, for example, the name property with a specific value exists in the objects array, we could do it in the following ways: JavaScript provides many functions that can solve your problem without actually implementing the logic in a general cycle. Let's suppose we have an array of objects like the following:
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